Operations with Integers Class 7 Extra Questions Maths Part 2 Chapter 2 - #NCSOLVE 📚

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Class 7 Operations with Integers Extra Questions

Class 7 Maths Chapter 2 Operations with Integers Extra Questions

Operations with Integers Extra Questions Class 7

Question 1.
Find the product for each of the following:
(a) (-9) × 5 × 3
(b) 3 × (-17) × (-2)
(c) (-13) × (-14) × (-1)
(d) 16 × 23 × 15
(e) (-25) × (-4) × (-3) x 5
(f) (-20) × (-A) × (-5) x g
Solution:
(a) (-9) × 5 × 3 = ×(9 × 5) × 3 = 15 × 3 =-135

(b) 3 × (-17) × (-2) = -(3 × n) x (-2) = -51 × (-2)
= +(51 × 2)
= +102 or 102

(c) (-13) × (-14)× (-1) = + (13 × 14) × (-1)
= +182 × (-1) =-182

(d) 16 ×23 × 15 = 16 × 345 = 5520

(e) (-25) × (-4) × (-3) × 5= +(25 × 4) × (-3) x 5
= 100 × (-3) × 5 = -(100 x 3) × 5 = -1500

(f) (-20) × (-4) × (-5) x 8
= – (20 × 4 × 5 × 8)
= -(3200) = -3200

Question 2.
A milk container holds 1,250 litres of milk. Due to a small leak, the amount of milk decreases at the rate of 5 litres per hour. How much milk will remain in the container after 15 hours?
Solution:
Total quantity of milk in the container = 1,250 litres.
Since the container is leaking, the quantity of milk decreases at the rate of 5 litres per hour.
Therefore, the quantity of milk leaked in 15 hours = 15 × 5 = 75 litres.
Thus, the quantity of milk left in the container after 15 hours = 1,250 – 75 = 1,175 litres.

Question 3.
Find the product:
(a) (-3) × (-3) × (-3) × (-3)
(b) (-4) × (-4) × (-4) × (-4) × (-4)
Solution:
We know that

• The product of an even number of negative numbers is positive.
• The product of an odd number of negative numbers is negative.

(a) (-3) × (-3) × (-3) × (-3) = 81
(b) (-4) × (-4) × (-4) × (-4) × (-4) = -1024

Question 4.
In a quiz, (+5) marks are awarded for every correct answer and (-1) mark is deducted for every incorrect answer.
(a) Ananya answered all questions. She got 12 correct answers and scored 50 marks. How many answers were incorrect?
(b) Vihaan got 8 correct answers. His score was 29 marks. How many questions did he attempt in total?
Solution:
(a) Total score = (Marks for correct answers) – (Marks deducted for incorrect answers)
12 x 5 – 1 x Incorrect answers = 50
60 – 1 x Incorrect answers = 50
Incorrect answers = 10

(b) Total score = 8×5-1 x Incorrect answers = 29
40 – Incorrect answers = 29
Incorrect answers = 11
Total number of questions attempted = Correct + Incorrect = 8 + 11 = 19

Question 5.
Simplify the following expressions:
(a) 20-(25-10 = 2)
(b)(-6)-(-18) + (-3) + (-5)×4
Solution:
(a) 20-(25- 10 – 2) = 20 – (25 – 5) = 20 – 20 = 0
(b) (-6) – (-18 = -3) + (-5 x 4) = (-6) – (6) + (-20)
= -6 – 6 – 20 = -32

Question 6.
A few labourers were given a contract to dig a well. On the first day, they dug to a depth of 15 metres. From the second day onwards, they dug 10 metres deep every day. What is the depth of the well at the end of 5 days?
Solution:
The depth of well is considered as a negative integer because they are digging downwards.
The depth on each day can be expressed as follows:
Day 1: -15 m; Day 2: -10 m; Day 3: -10 m; Day 4: -10 m; Day 5: -10 m
At the end of 5 days, the depth of the well is:
-15 m + 4 x (-10 m) = -55 metres, meaning they have dug 55 metres in total.

Question 7.
The temperature gauge at a weather station shows a temperature at +20°C at 6 a.m. The temperature decrease at a constant rate of 2°C per hour. At what time will the temperature reach -10°C?
Solution:
Initial temperature at 6 a.m. is 20°C.
Temperature decreases by 2°C per hour.
We need to find when the temperature will reach -10°C
Total decrease in temperature = 20 – (-10) = 30°C
Time taken to decrease by 30°C = \(\frac{30}{2}\) =15 hours
Starting from 6 a.m, the temperature will take 15 hours to reach -10°C.
6 a.m. + 15 hours = 9 p.m.
Thus, the temperature will reach -10°C at 9 p.m.

Question 8.
Observe the pattern when multiplying 4 with integers from 3 to -3.
Solution:
4 × 3=12 ; 4 × 2=8 ; 4 × 1=4 ; 4 × 0=0; 4 ×(-1)=-4 ; 4 ×(-2)=-8 ; 4 ×(-3)=-12.
Pattern Observed: Products decrease by 4 each time as n decreases by 1
Positive × positive = positive,
positive × negative = negative.
Sequence : 12,8,4,0,-4,-8,-12

Question 9.
A quiz competition has 40 questions. Each correct answer gives 6 marks, and each wrong answer deducts 3 marks. What are Riya’s total marks if she answered 25 questions correctly and 15 questions wrongly?Solution:
Marks from correct answers: 25 × 6=150
– Marks deducted for wrong answers:
15 × (-3)=-45
– Total marks: 150+(-45)=105
Riya’s total marks =105.

Question 10.
A submarine moves above and below the sea level. Positions above the sea level are positive integers, and positions below sea level are negative integers.
(a) The submarine descends at a speed of 4 metres per minute. If it starts from sea level (0), where will it be after 20 minutes?
(b) If it starts from 10 metres above sea level, where will it be after 15 minutes of descending?
Solution:
(a) From sea level: 20 ×(-4)=-80
Position =-80m(80m below sea level)

(b) From 10 m above sea level:
10+(15 ×-4)=10-60=-50
Position =-50m (50 m below sea level).

Operations with Integers Class 7 Short Question Answer

Question 1.
16 × (-9)+(-8) × (-9)
(a) -72
(b) 72
(c) 70
(d) 71
Solution:
16 × (-9)+(-8) × (-9)
= 16+(-8) × (-9)
= 8 × (-9)
= -72
Hence (a) is correct option.

Question 2.
1569 ×  887 – 569 × 887
(a) 887000
(b) -887000
(c) 80000
(d) -80000
Solution:
1569 × 887-569 × 887
= (1569-569) × 887
= 1000 × 887
= 887000
Hence, (a) is correct option.

Question 3.
Add :
(a) -18, 14
(b) -26,-3
(c) 46, -46
Solution:
(a) -4
(b) -29
(c) 0

Question 4.
Starting from (-3) × 4, find (-3) × (-3)
Solution:
Do yourself.

Question 5.
Find: 37 – (- 15 ) – 2:
Solution:
-24

Question 6.
If a=-8, b=4 and c=1, then find (a × b) +(a × c)
Solution:
-40

Question 7.
15+(-8)= ?
Solution:
7

Question 8.
Find the additive inverse of:
(a) -83
(b) 256
(c) 0
(d) -2001
Solution:
(a) 83
(b) -256
(c) 0
(d) 2001

Question 9.
Which is greater: \(\frac{1}{4}\) of \(\frac{8}{7}\) or \(\frac{4}{7}\) of \(\frac{6}{8}\)?
Solution:
\(\frac{4}{7}\) of  \(\frac{6}{8}\)

Question 10.
I was 4 km east of my home; now I am 3 km west of my home. How many km did I travel? I was 4 km east of my home. Now I am 3 km west of my home. How many km did I travel?
Solution:
7 km

Question 11.
A cement company earns a profit of Rs. 8 per bag of white cement sold and a loss of Rs. 5 per bag of grey cement sold.
(a) The company sells 3,000 bags of white cement and 5,000 bags of grey cement in a month. What is its profit or loss?
(b) What is the number of white cement bags it must tell to have neither profit nor loss, if the number of grey bags sold is 6,400 bags.
Solution:
(a) = (3000 × 8)-(5000 × 5)
= 24000 – 25000 = – 1000
∴ Loss = Rs. 1000

(b) Let x be the number of white cement bags sold. According to the question, we get

 

 

Operations with Integers Class 7 Long Short Question Answer

 

 

Operations with Integers Class 7 Case Based Questions

 

Operations with Integers Extra Questions for Practice

 

 

 

The post Operations with Integers Class 7 Extra Questions Maths Part 2 Chapter 2 appeared first on Learn CBSE.

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